Re: Perl beginner question (ya know how beginners are!)

You may have only specified three parameters, however in your case the
filename itself is the first parameter passed to your script.

HTH,

-M
----- Original Message -----
From: Alberto.�.Vallini <vallinis(at)yahoo.com>
To: <hwg-languages(at)mail.hwg.org>
Sent: Thursday, September 07, 2000 8:24 PM
Subject: Perl beginner question (ya know how beginners are!)


Perl beginner dilemma: I have the following code: when
printing the hash, it assigns to the first key no
contents: how happens? I was expecting to get assigned
values ONLY to actual inputs provided at the STDIN!
Where does the first empty key comes out from, thus
determining an amount of ***4*** hash values printed,
since I only provided ***3*** inputs at the prompt?

Code:
%example=();
$assign="w";
while ($assign ne "") {
chomp($assign=<STDIN>);
$example{$assign}="this is a value assigned on the fly
to KEY: $assign";
}


foreach $key (keys %example) {
print($key."=".$example{$key}."\n");
# printing instruction above gives the following
output, with input: one.two, three:
# =this is a value assigned on the fly to KEY:
# one=this is a value assigned on the fly to KEY: one
# two=this is a value assigned on the fly to KEY: two
# three=this is a value assigned on the fly to KEY:
three

# QUESTION: why we get a first key with unassigned
contents? ie: " =this"
}

Thank you for any possible help (in plain simple words
eheh)!


=====
Alberto.�.Vallini - vallinis(at)yahoo.com
http://www.geocities.com/earthalliances/
"when everything else fails, sleep"

__________________________________________________
Do You Yahoo!?
Yahoo! Mail - Free email you can access from anywhere!
http://mail.yahoo.com/

HWG: hwg-languages mailing list archives, maintained by Webmasters @ IWA