Re: [Re: [Re: calculating distance based on zip/postal codes]]
by Zach Kenyon <zantispam(at)netscape.net>
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Date: |
15 May 00 20:47:35 CDT |
To: |
hwg-business <hwg-business(at)hwg.org> |
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todo: View
Thread,
Original
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Jan Theodore Galkowski <jtgalkowski(at)alum.mit.edu> wrote:
> > No system is perfect, even stating a city doesn't help as from one en=
d =
> > to the other can easily be a 45 minute drive.
> Well, for this application, you might be able to use the arccosine rule=
=2E
> You just treat latitude and longitude as if they were rectangular =
> cartesian coordinates and calculate a distance: If the result is =
> smaller than some threshold amount, you simply announce the people are =
> "close". Otherwise you use the arccosine rules. This idea will work =
> for any place having latitudes closer to the equator than the arctic or=
=
> antarctic circles.
Three things:
#1: Define `close' (and `not far' doesn't count :-)
#2: Isn't there a page on the JPL website ( http://www.jpl.nasa.gov ) tha=
t
will calculate latitude and longitude based on your address? This would
probably provide numbers close enough to work with. (I didn't see anythi=
ng on
the MIT website; maybe you would know?)
#3: In your last mail, you said in part:
> Vector analysis is good for this. There are also more numerically stabl=
e =
> representations, such as quaternions (although, apart from religious =
> considerations, it's hard to make a case for them versus, say, spin =
> matrices, or rotation matrices themselves) or Rodrigues parameters (a =
> favorite of mine). =
> =
> In serious work, error analysis on the sphere is an important =
> consideration and, if the standard angular deviations are anything
> but tiny, involves some non-standard stuff which is the subject of =
> spherical statistics and spherical regression, eg, paleomagnetic =
> calculations.
Where can I go to get more info on this?
--Jedi Hacker(apprentice) and Code Poet
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