RE: a reg-exp assist - js
by "Micah R. Condon" <micahc(at)webdezyne.com>
|
| Date: |
Fri, 26 Apr 2002 09:16:34 -0600 |
| To: |
"'Deborah Rorabaugh'" <librarian(at)shadolibrary.org>, <hwg-techniques(at)hwg.org> |
| In-Reply-To: |
shadolibrary |
| |
todo: View
Thread,
Original
|
|
re = /\$([0-9]+),?([0-9]+)/g;
a = $40,000;
a = a.replace(re,"$1$2");
-----Original Message-----
From: owner-hwg-techniques(at)hwg.org
[mailto:owner-hwg-techniques(at)hwg.org]On Behalf Of Deborah Rorabaugh
Sent: Friday, April 26, 2002 8:12 AM
To: hwg-techniques(at)hwg.org
Subject: RE: a reg-exp assist - js
I don't think you can combine them - when combined it will be looking for
the string '$,' to remove, not '$' then ','.
Deborah R.
-----Original Message-----
From: owner-hwg-techniques(at)hwg.org
[mailto:owner-hwg-techniques(at)hwg.org]On Behalf Of Michael Gerholdt
Sent: Thursday, April 25, 2002 8:55 AM
To: hwg-techniques(at)hwg.org
Subject: a reg-exp assist - js
re = /\$/g;
r2 = /,/g;
I can get these to work independently, but how can I combine them into one
pattern in JS?
I would think
re = /\$,/g;
a = $40,000;
a = a.replace(re,"");
so a = 40000 in the end.
but I get NAN when I try this.
In the meantime, I'm doing:
re = /\$/g;
r2 = /,/g;
a = a.replace(re,"");
a = a.replace(r2,"");
which yields the correct results .. but surely this is not necessary!
Thanks,
Mike
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