RE: Perl year
by Rob Prentice <RJP(at)clickdms.com>
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| Date: |
Mon, 26 Jun 2000 16:14:03 +0100 |
| To: |
"'FODAC(at)aol.com'" <FODAC(at)aol.com>, hwg-techniques(at)mail.hwg.org |
| |
todo: View
Thread,
Original
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try this...
($second, $minuet, $hour, $dayOFmonth, $month, $year, $weekday,
$dayOFyear, $isDST) = localtime(time);
$realmonth = $month + 1;
$longyear = ($year + 1900);
printf('%02d:%02d:%02d %02d/%02d/%02d', $hour, $minuet, $second,
$dayOFmonth, $realmonth, $longyear);
should work:)
-----Original Message-----
From: FODAC(at)aol.com [mailto:FODAC(at)aol.com]
Sent: 26 June 2000 10:38
To: hwg-techniques(at)mail.hwg.org
Subject: Perl year
I figured out my guestbook erasing problem. I do have one more Perl
question.
I'm using the localtime function for a date when entries are submitted
and I'm getting 20100 instead of 2000 for the year. I reduced the field
size by one and got 205. This is on a UNIX server. Could someone give
me a brief explanation of how this function works?
Thanks,
Kevin Riggs
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